0=-0.12x^2=3x

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Solution for 0=-0.12x^2=3x equation: 



0=-0.12x^2=3x

We move all terms to the left:

0-(-0.12x^2)=0

We add all the numbers together, and all the variables

-(-0.12x^2)=0

We get rid of parentheses

0.12x^2=0

a = 0.12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·0.12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{0.24}=0$

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